Matthew van Eerde's web log
I am a Software Development Engineer in Test working for the Windows Sound team. You can contact me via email: mateer at microsoft dot com
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I'm reading Joan Daemen and Vincent Rijmen's book The Design of Rijndael and I'm giving myself a refresher course on group theory.
Key to the encryption standard is the Galois field on 256 elements GF(2^{8}). A multiplication table of 256 elements by 256 elements quickly becomes a wall of text, so let's reason by analogy and look at GF(2^{2}).
There are a number of ways to represent elements of the field; we'll start by representing them as polynomials with degree at most 1, and with integer coefficients modulo 2. There are four such polynomials: {0, 1, x, x + 1}.
Here are the addition and multiplication tables:
Hold on. What's that funny-looking m?
It's a "reduction polynomial" which brings the product back down to degree 1 or less. It has to be a polynomial of degree 2. There are four such polynomials: let's try each and see what we get.
Note that the first three polynomials all factor into products of lower-degree polynomials: x^{2} = x(x), x^{2} + 1 = (x + 1)(x + 1), x^{2} + x = x(x + 1). Only x^{2} + x + 1 is prime; and this prime reduction polynomial generates a complete multiplication table with no 0s. This is a necessary condition to be a field. Our final tables are:
We can also write our elements in binary form: 0 => 00, 1 => 01, x => 10, and x + 1 => 11. In this notation our tables become:
Rijndael works in GF(2^{8}) and uses a reduction polynomial of x^{8} + x^{4} + x^{3} + x + 1. They say this is prime. I sure hope so.
Note that the + table for the binary notation is just XOR.
you suck!
Sorry I upset you; can you elaborate?