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• Why Do Initializers Run In The Opposite Order As Constructors? Part Two

  As you might have figured out, the answer to last week's puzzle is "if the constructors and initializers run in their actual order then an initialized readonly field of reference type is guaranteed to be non null in any possible call. That guarantee cannot Read More... Posted Monday, February 18, 2008 7:25 AM by Eric Lippert | 41 Comments Filed under: C#, Puzzles, Immutability

• Why Do Initializers Run In The Opposite Order As Constructors? Part One

  Pop quiz! What do you expect the output of this program to be? using System; class Foo { public Foo(string s) { Console.WriteLine("Foo constructor: {0}", s); } public void Bar() { } } class Base { readonly Foo baseFoo = new Foo("Base initializer"); public Read More... Posted Friday, February 15, 2008 3:01 PM by Eric Lippert | 30 Comments Filed under: C#, Puzzles, Immutability