Saveen Reddy's blog

A Simple LINQ Example with System.Reflection and System.Drawing.Color

Recently I needed to get see all the RGB values for the System.Drawing.Color values (for example System.Drawing.Color.Red, System.Drawing.Color.Aqua, etc.).

It's a very simple task that shows some of the expressive simplicity of LINQ.

Here's the sample using the LINQ method syntax:

using System;
using System.Linq;

namespace CmdLineTest
{
    internal class Program
    {
        [STAThread]
        private static void Main(string[] args)
        {
            var color_type = typeof(System.Drawing.Color);

            var color_properties = color_type.GetProperties()
                .Where(m => m.PropertyType == color_type );

            foreach (var color_property in color_properties)
            {
                var cur_color = (System.Drawing.Color)color_property.GetValue(null, null);
                uint rgb_int = (uint)cur_color.ToArgb() & (0x00ffffff);
                Console.WriteLine(" {0} = ({1},{2},{3}) = 0x{4:X00000000}",
                    color_property.Name,
                    cur_color.R, cur_color.G, cur_color.B,
                    rgb_int );
            }
        }
    }
}

Here's the sample using the LINQ query syntax:

using System;
using System.Linq;

namespace CmdLineTest
{
    internal class Program
    {
        [STAThread]
        private static void Main(string[] args)
        {
            var color_type = typeof(System.Drawing.Color);

            var color_properties = from prop in color_type.GetProperties()
                                   where prop.PropertyType == color_type
                                   select prop;

            foreach (var color_property in color_properties)
            {
                var cur_color = (System.Drawing.Color)color_property.GetValue(null, null);
                uint rgb_int = (uint)cur_color.ToArgb() & (0x00ffffff);
                Console.WriteLine(" {0} = ({1},{2},{3}) = 0x{4:X00000000}",
                    color_property.Name,
                    cur_color.R, cur_color.G, cur_color.B,
                    rgb_int );
            }
        }
    }
}

The output will look like this

Transparent = (255,255,255) = 0xFFFFFF
AliceBlue = (240,248,255) = 0xF0F8FF
AntiqueWhite = (250,235,215) = 0xFAEBD7
Aqua = (0,255,255) = 0xFFFF
Aquamarine = (127,255,212) = 0x7FFFD4
Azure = (240,255,255) = 0xF0FFFF
Beige = (245,245,220) = 0xF5F5DC
Bisque = (255,228,196) = 0xFFE4C4
Black = (0,0,0) = 0x0
BlanchedAlmond = (255,235,205) = 0xFFEBCD
Blue = (0,0,255) = 0xFF
BlueViolet = (138,43,226) = 0x8A2BE2
Brown = (165,42,42) = 0xA52A2A
BurlyWood = (222,184,135) = 0xDEB887
CadetBlue = (95,158,160) = 0x5F9EA0
Chartreuse = (127,255,0) = 0x7FFF00

For the record: my favorite is System.Drawing.Color.Tomato